Show that for strong as well as weak magnetization,
$$
\mu_0 M=\frac{\chi}{1+\alpha \chi} B_{0 I}=\frac{\chi}{1+(\gamma+\alpha) \chi} B_0 .
$$
Hence, show that, for a sample described by the Curie-Weiss law, the equation of state can be written
$$
\frac{\mu_0 M}{B}=\frac{a}{T-T_c^v}
$$
where $T_c^{\prime}=T_c-\alpha a$ for $B=B_{0 I}$ and $T_c^{\prime}=T_c-(\gamma+\alpha) a$ for $B=B_0$. Hence for strong magnetization the Curie-Weiss law is modified simply by a shift in the parameter $T_c$. Note, this is not strictly the transition temperature, but a parameter in a model that is valid for $T \gg T_c$ (the actual critical point is reached at a temperature slightly below this $T_c$ ).