Question
Show that $\forall x P(x) \vee \forall x Q(x)$ and $\forall x \forall y(P(x) \vee Q(y))$ where all quantifiers have the same nonempty domain, are logically equivalent. (The new variable $y$ is used to combine the quantifications correctly.)
Step 1
Step 1: We start with the given expression $\forall x P(x) \vee \forall x Q(x)$. Show more…
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Key Concepts
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a) Show that $\forall x P(x) \wedge \exists x Q(x)$ is logically equivalent to $\forall x \exists y(P(x) \wedge Q(y)),$ where all quantifiers have the same nonempty domain. b) Show that $\forall x P(x) \vee \exists x Q(x)$ is equivalent to $\forall x \exists y$ $(P(x) \vee Q(y)),$ where all quantifiers have the same nonempty domain.
The Foundations: Logic and Proofs
Nested Quantifiers
Show that the two statements $\neg \exists x \forall y P(x, y)$ and $\forall x \exists y \neg P(x, y),$ where both quantifiers over the first variable in $P(x, y)$ have the same domain, and both quantifiers over the second variable in $P(x, y)$ have the same domain, are logically equivalent.
Use rules of inference to show that if $\forall x(P(x) \vee Q(x))$ and $\forall x((\neg P(x) \wedge Q(x)) \rightarrow R(x))$ are true, then $\forall x(\neg R(x) \rightarrow$ $P(x)$ is also true, where the domains of all quantifiers are the same.
Rules of Inference
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