00:01
Hello, and in this question here, we're going to show that the maths of special relativity is consistent with the fact that you can't travel faster than speed of life.
00:09
To do this, we're going to consider an initial coordinate system at rest, which is s.
00:16
The vertical axis is time and the horizontal axis is position.
00:22
We have a second coordinate system, s prime, where s prime moves at a relative velocity v1 relative to s.
00:32
The vertical axis is t prime and the horizontal axis is x prime.
00:40
For an observer in s prime, there is an object and this object is traveling with the velocity v2.
00:50
So this velocity v2 is the velocity of the object relative to an observer in s prime.
00:58
We want to find out what the velocity of this object v2 is relative to an observer.
01:06
Classically we would just expect that you would add the velocity of s relative to s prime and then the velocity of the object relative to s prime and that would be the velocity of the object to an observer in s however this equation would allow you to travel faster than the speed of light so this cannot be true, so we use special relativity instead.
01:36
So to derive a formula for what the object travelling, for the velocity of the object in s, we will introduce the lorentz transforms between the two coordinate frames as x prime equals gamma multiplied by x minus v1 multiplied by where v1 is the relative velocity between s and s prime and t prime is equal to gamma multiplied by t minus v1 times x over c squared where c is the speed of light and gamma is equal to the square root of one divided by v1 squared over c squared so we will now introduce infinitesimal versions of these lorentz transforms and say that dx prime is is equal to gamma dx minus v1 d t and d t prime is equal to gamma d t minus v1 d x over c squared so we have two equations equation one and equation two let's divide equation one by equation two we get d x prime divided by d t prime our gmas will cancel dx minus v1 d t all divided by d t minus v1 d x over c squared okay so what is d x prime divided by d t prime well we would say d x d t is the velocity of the object in x and this here this velocity which we're going to call v.
03:38
This here is going to be the velocity that we want to show is less than the speed of life.
03:45
This velocity here, in analogy, we will say that this is the velocity of the object.
03:56
So of the same object, this velocity here, this one here, is the velocity of the same object as this one here.
04:07
However, the crucial distance that this will be the velocity relative to an observer.
04:11
In s prime.
04:14
I've got a color there, but in s prime.
04:20
So what is the velocity of the object relative to the observer in s prime? well, if we scroll back up here in our diagram, we see here that that velocity is v2, which equals v2...