We have equation (8) as $u''+ \frac{1}{t} u' + \left(\frac{a^2-1}{t^2}-b\right)u=0$.
Substituting $u_2=(\ln t) t^{(1-a) / 2}$ into this equation, we get:
$u_2''+ \frac{1}{t} u_2' + \left(\frac{a^2-1}{t^2}-b\right)u_2=0$
Now, let's calculate the derivatives of
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