00:01
All right, so here we are given a and b are positive integers.
00:08
And we want to prove that the product of a &b is equal to the, okay, this common divisor of a &b multiplied by the least common multiple of a &b.
00:27
Okay, so we'll let, say, p1 to pk be the, primes of the prime factorization of a and b.
00:46
That would give us a in the form of p1 to some power times p2 to some power and that power could be zero right if it doesn't exist in there.
01:03
And we'll represent b the same way.
01:09
But of course their respective powers could be different.
01:13
So you want to make sure we note that in our notation.
01:20
Okay, we'll so if we have this representation, then the greatest common divisor of a and b is going to be p1 times the to the power of the minimum of a1 and b1.
01:42
And then we repeat this process, so times the second prime to the power of the minimum a2b2, right? and if one of them happened to be zero, then of course that element wouldn't exist, and that's what we would want.
02:02
To see.
02:10
Okay, and then we also note then that the least common multiple we find similarly, right, instead it's going to be the maximum.
02:19
So we have the exact same thing as before.
02:21
I wish i could just sort of copy and paste it, but instead we were taking the powers at the maximum.
02:37
Okay, so then we want to determine the product of the greatest common divisor in least common multiple.
02:52
So we want to use the fact.
02:54
Let's make a little note in here...