Question
Show that if $A$ and $B$ are sets and $A \subset B$ then $|A| \leq|B|$
Step 1
We are given two sets $A$ and $B$ such that $A$ is a subset of $B$. We need to show that the cardinality of $A$ is less than or equal to the cardinality of $B$. Show more…
Show all steps
Your feedback will help us improve your experience
Angelo Rendina and 70 other Algebra educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
Show that if $A$ and $B$ are sets $|A|=|B|,$ then $|\mathcal{P}(A)|=$ $|\mathcal{P}(B)| .$
Basic Structures: Sets, Functions, Sequences, Sums,and Matrices
Cardinality of Sets
Show that if $A, B,$ and $C$ are sets such that $|A| \leq|B|$ and $|B| \leq|C|,$ then $|A| \leq|C|$ .
Show that if $A$ and $B$ are sets with the same cardinality, then $|A| \leq|B|$ and $|B| \leq|A|$
Transcript
18,000,000+
Students on Numerade
Trusted by students at 8,000+ universities
Watch the video solution with this free unlock.
EMAIL
PASSWORD