00:01
In this problem, we are going to show a certain matrix equation holds, given that a, b, and a plus b are invertible matrices with the same size.
00:12
Now, what we have been asked to show, the left -hand side of the identity is a -times -a -inverse plus b -inverse times b -times -a -plus -b -inverse.
00:27
Inverse, we need to show that this is equals to i, which is the identity matrix.
00:36
Now for this first of all, let us apply the distributive law for the first two terms.
00:41
Then we will have a a inverse plus a b inverse and with this we multiply b and a plus b inverse.
00:53
Now a a inverse will be the identity matrix i because the product of any matrix with its inverse is equal to the identity matrix, the other term remains unchanged.
01:08
Next, we will apply the distributive law again for the first two terms.
01:13
So, we will have i times b plus a, b inverse times b.
01:21
With this, we multiply a plus b inverse inverse.
01:25
Now, since the product of the identity matrix with any matrix is that matrix itself, so ib is equals to b.
01:32
Next we have a times b inverse b.
01:35
Now b inverse b inverse b inverse b inverse i because the product of any matrix with its inverse is the identity matrix.
01:43
So this is what we are left with...