Question
Show that if $A^T=-A$ is any skew-symmetric matrix, then its Cayley Transform $Q=(\mathrm{I}-A)^{-1}(\mathrm{I}+A)$ is an orthogonal matrix. Can you prove that $\mathrm{I}-A$ is always invertible?
Step 1
If $A$ is a square matrix, then the Cayley Transform $Q$ of $A$ is given by: \[ Q = (\mathrm{I} - A)^{-1}(\mathrm{I} + A) \] where $\mathrm{I}$ is the identity matrix of the same size as $A$. Show more…
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