Question
Show that if $p c \ll m_{0} c^{2}$, the relativistic correction [Eq. (14.16)] is given by$$\Delta E_{r}=-\int \Psi_{n}^{*} \frac{\hbar^{4}}{8 m^{2} c^{2}} \nabla^{4} \Psi_{n} d v$$
Step 1
This condition implies that the momentum of the particle is much less than its rest mass energy. This is the non-relativistic limit, where the kinetic energy of the particle is much less than its rest mass energy. Show more…
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