Question
Show that $\left(a_{1}, a_{2}, \ldots, a_{n}\right)+\left(b_{1}, b_{2}, \ldots, b_{n}\right)=\left(b_{1}, b_{2}, \ldots, b_{n}\right)+\left(a_{1}, a_{2}, \ldots, a_{n}\right)$.
Step 1
Step 1: First, we define the addition of two n-tuples as follows: \[(a_{1}, a_{2}, \ldots, a_{n})+(b_{1}, b_{2}, \ldots, b_{n})=(a_{1}+b_{1}, a_{2}+b_{2}, \ldots, a_{n}+b_{n})\] Show more…
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