Question
Show that $$\left|\begin{array}{lll}1 & b c & b+c \\1 & c a & c+a \\1 & a b & a+b\end{array}\right|=(b-c)(c-a)(a-b)$$
Step 1
This gives us the new matrix: $$\left|\begin{array}{lll} 1 & b c & b+c \\ 0 & c a - b c & c - b \\ 0 & a b - b c & a - b \end{array}\right|$$ Show more…
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