Show that $\lim _{n \rightarrow \infty} P\left(\left|X_{n}\right|>\epsilon\right)=0$ for every $\epsilon$ if and only if given any $\epsilon$, there exists $n_{0}(\epsilon)$ such that
$$
P\left(\left|X_{n}\right|>\epsilon\right)<\epsilon \text { for } n>n_{0}(\epsilon)
$$
This is also equivalent to: given any $\delta$ and $\epsilon$, there exists $n_{0}(\delta, \epsilon)$ such that
$$
P\left(\left|X_{n}\right|>\epsilon\right)<\delta \text { for } n>n_{0}(\delta, \epsilon) .
$$
[Hint: consider $\epsilon^{\prime}=\delta \wedge \epsilon$ and apply the first form.