00:01
Okay, so here we let s sub n be the nth partial sum of the series, where we have a series, k going from 1 to infinity of k times x to the k minus 1, where the absolute value of x is less than 1.
00:13
So therefore, we get that s sub n is equal to 1 plus 2x plus 3x squared and so on, up to plus n times x to the n minus 1.
00:22
So we get then that we have s sub n minus 2, x.
00:30
X times s of n plus x squared times s sub n is equal to 1 minus n plus 1 times x sub n plus n plus n and then that implies that we end up getting s sub n being equal to 1 minus n plus 1 times x to the n plus n plus n times x to the n plus n all divided by the quantity 1 minus x squared.
01:05
Now we can choose an epsilon greater than 0, such that we get 1 plus epsilon times the absolute value of x is less than 1.
01:17
So since we have that n to the 1 over n is going to approach 1.
01:24
There exists a k here that is less than 1 plus epsilon...