Question
Show that the area of this right triangle is$$\frac{1}{2} b c \sin A$$(Angle can't copy)
Step 1
We know that the area of a triangle is given by the formula $\frac{1}{2} \times base \times height$. In this case, we consider side b as the base and side a as the height. So, the area of the triangle is $\frac{1}{2}ab$. Show more…
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