Question
Show that the circumference of the unit circle is equal to\begin{equation}2 \int_{-1}^{1} \frac{d x}{\sqrt{1-x^{2}}} \quad(\text { an improper integral })\end{equation}
Step 1
We need to show that the circumference of the unit circle is equal to the given integral. The unit circle is a circle with radius 1 centered at the origin, and its circumference is known to be \(2\pi\). Show more…
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Show that the circumference of the unit circle is equal to $$ 2 \int_{-1}^{1} \frac{d x}{\sqrt{1-x^{2}}} \quad(\text { an improper integral }) $$ Evaluate, thus verifying that the circumference is 2$\pi .$
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4) Show that the circumference of the unit circle is equal to 2 integral from -1 to 1 of 1/sqrt(1-x^2) dx (an improper integral) Evaluate, thus verifying that the circumference is 2pi.
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