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Show that the complete chemical equation, the total ionic equation, and the net ionic equation for the reaction represented by the equation $\mathrm{KI}(a q)+\mathrm{I}_{2}(a q) \rightleftharpoons \mathrm{KI}_{3}(a q)$ give the same expression for the reaction quotient. $\mathrm{KI}_{3}$ is composed of the ions $\mathrm{K}^{+}$ and $\mathrm{I}_{3}^{-}$.

Hence, the reaction quotient for total chemical equation, total ionic equation and net ionic equation has same expression.

Chemistry 102

Chapter 13

Fundamental Equilibrium Concepts

Chemical Equilibrium

Aqueous Equilibria

Drexel University

University of Maryland - University College

University of Kentucky

University of Toronto

Lectures

03:07

A liquid is a nearly incom…

04:38

A liquid is a state of mat…

05:10

Write balanced complete io…

01:09

Write two sets of equation…

07:00

Predict the products and w…

03:14

Complete the following neu…

10:25

Write a balanced net ionic…

14:22

Write balanced net ionic e…

01:38

Write the formula equation…

08:49

Write ionic and net ionic …

04:26

06:44

Write ionic and net ionic…

02:38

12:50

0:00

Write the balanced formula…

07:30

06:45

Write a total ionic equati…

12:48

Predict the products for e…

05:18

Balance the following equa…

06:30

05:28

Complete each of the follo…

Write a balanced ionic equ…

love one, This is Ricky. And today we're gonna work on problem number 12 which, where we will be showing the total chemical equation total I ionic equation and that ionic equation How they all have the same reacting question. So first, let's write down each of the equations. So the total chemical equation, the total Ionic equation and Dean and Ionic equation. Now, let's go ahead and, uh, writes down each of the reaction potions. Um, so remember that we ask you is equal to products of the reactant ce. So yeah. Okay, I three over K I I'm side to and we can simplify this, huh? Two Just I three minus over. I minus unsighted to next. Let's do this for the total ionic equations. We have Q people, too. I three que plus over. I'm minus ones. I too, times k plus, um, let's get rid of our confounding factors and we get the same reaction questioned as the total reaction. And lastly, we're going to be writing our reaction quotient for our Net Ionic equation. So we have products, reactions, and as you can see, they're all the same. So help this feels so formal issue in the next one

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