00:01
We are trying to prove that the first trisection point occurs at a certain point that was listed in the problem.
00:06
And then we're going to use the midpoint between that first trisection point and the second point to calculate where the second trisection point is.
00:16
We do know that if it's a trisection point.
00:18
It should be one -third of the distance from the first to the second point.
00:23
So we're starting at x1, y -1.
00:25
So the x coordinate of the first point, the first trisection point is x sub 1 plus one third of the distance from x1 to x2, which would be one -third x2 minus x -1.
00:42
Y -coordinate looks similar.
00:44
Y1 plus one -third, y2 minus y -1.
00:52
We could distribute the one -third that would give us x sub 1 plus 1.
00:58
Plus one -third x2 minus one -third x1, comma, y1, plus one -third y2, minus one -third y -2.
01:17
There are some common factors we can combine there.
01:22
The x -1 minus one -third x -1, that's one minus a third, which is two -thirds.
01:28
So let's just change this to two -thirds x sub one.
01:38
Likewise, we can do that with the y -1s.
01:40
That will give us, when we combine them, gives us two -thirds y -1...