Show that the cross section for elastic scattering of unpolarized electrons from spinless point-like particles is
$$
\left.\frac{d \sigma}{d \Omega}\right|_{\text {Lab, }}=\left(\frac{\alpha^2}{4 E^2 \sin ^4 \frac{\theta}{2}}\right) \frac{E^{\prime}}{E} \cos ^2 \frac{\theta}{2},
$$
where as before we neglect the mass of the electron. Justify using (6.18) with $L_{\mu \nu}^{\text {muon }}$ replaced by $\left(p+p^{\prime}\right)_\mu\left(p+p^{\prime}\right)_v$. Comparing the cross section with that for $\mathrm{e}^{-} \mu^{-} \rightarrow \mathrm{e}^{-} \mu^{-}$, we see that the $\sin ^2(\theta / 2)$ in $(6.50)$ is due to scattering from the magnetic moment of the muon.