Question
Show that the cubic $p(x)=x^{3}+a x^{2}+b x+c$ has extreme values iff $a^{2} > 3 b$
Step 1
Step 1: First, we are given the cubic function $p(x)=x^{3}+a x^{2}+b x+c$. Show more…
Show all steps
Your feedback will help us improve your experience
Nick Johnson and 50 other Calculus 1 / AB educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
Show that the cubic $p(x)=x^{3}+a x^{2}+b x+c$ has extreme values iff $a^{2}:-3 b$
The Mean-Value Theorem; Applications of the First and Second Derivatives
Endpoint Extreme Values; Absolute Extreme Values
Consider the general cubic polynomial $f(x)=x^{3}+a x^{2}+b x+c,$ where $a, b,$ and $c$ are real numbers. a. Prove that $f$ has exactly one local maximum and one local minimum provided $a^{2}>3 b$ b. Prove that $f$ has no extreme values if $a^{2}<3 b$
Applications of the Derivative
What Derivatives Tell Us
Consider the general cubic polynomial $f(x)=x^{3}+a x^{2}+b x+c,$ where $a, b,$ and $c$ are real numbers. a. Prove that $f$ has exactly one local maximum and one local minimum provided that $a^{2} > 3 b$ b. Prove that $f$ has no extreme values if $a^{2} < 3 b$
Transcript
18,000,000+
Students on Numerade
Trusted by students at 8,000+ universities
Watch the video solution with this free unlock.
EMAIL
PASSWORD