Question
Show that the energy $E$ in eV of a photon is given by $E=1.241 \times 10^{-6} \mathrm{eV} \cdot \mathrm{m} / \lambda, \quad$ where $\lambda$ is its wavelength in meters.
Step 1
Step 1: The energy of a photon is given by the equation $E = h \cdot c / \lambda$, where $h$ is Planck's constant, $c$ is the speed of light, and $\lambda$ is the wavelength of the photon. Show more…
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Show that the wavelength $\lambda$ in $\mathrm{nm}$ of a photon with energy $E$ in $\mathrm{eV}$ is $\lambda=1240 / E.$
Show that the wavelength $\lambda$ in $\mathrm{nm}$ of a photon with energy $E$ in eV is $\lambda=1240 / E$
(II). Show that the energy $E$ (in electron volts) of a photon whose wavelength is $\lambda(\mathrm{nm})$ is given by $$ E=\frac{1.240 \times 10^{3} \mathrm{eV} \cdot \mathrm{nm}}{\lambda(\mathrm{nm})} $$
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