Question
Show that the energy-momentum relationship $E^{2}=p^{2} c^{2}+\left(m c^{2}\right)^{2}$ follows from the expressions $E=\gamma m c^{2}$ and $p=\gamma m u .$
Step 1
The energy of a particle is given by $E=\gamma m c^{2}$ and the momentum is given by $p=\gamma m u$. Show more…
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