Question
Show that the equation represents a circle, and find the center and radius of the circle.$$x^{2}+y^{2}+\frac{1}{2} x+2 y+\frac{1}{16}=0$$
Step 1
The equation is given as $x^{2}+y^{2}+\frac{1}{2} x+2 y+\frac{1}{16}=0$. We can rewrite this as $(x^{2}+\frac{1}{2}x+\frac{1}{16})+(y^{2}+2y+1)=1$. Show more…
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