Question
Show that the error in approximating $(27.1)^{5 / 3}$ by $(27)^{5 / 3}$ is bigger than $3 / 2$.
Step 1
Let \( f(x) = x^{5/3} \). We want to compare \( f(27.1) \) and \( f(27) \). Show more…
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You don't have a calculator; you may want to approximate (27.001)^2/3 by 27^2/3. Use the Mean Value Theorem to estimate the error in this approximation. To check that you are on the right track, test your numerical answer below: The magnitude of the error is less than (Enter an).
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In Exercises $59-67$, approximate using linearization and use a calculator to compute the percentage error. $$(1.2)^{5 / 3}$$
APPLICATIONS OF THE DERIVATIVE
Linear Approximation and Applications
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