Question

Show that the Fourier transform of $g(t)$ may be expressed as $$ G(f)=\int_{-\infty}^{\infty} g(t) \cos 2 \pi f t d t-j \int_{-\infty}^{\infty} g(t) \sin 2 \pi f t d t $$ Hence, show that if $g(t)$ is an even function of $t$, then $$ G(f)=2 \int_0^{\infty} g(n) \cos 2 \pi f t d t $$ and if $g(t)$ is an odd function of $t$, then $$ G(f)=-2 i \int_0^{\infty} g(t) \sin 2 \pi f t d t $$ Hence, prove that: \begin{tabular}{ll} If $g(t)$ is: & Then $G(f)$ is: \\ a real and even function of $t$ & a real and even function of $f$ \\ a real and odd function of $t$ & an imaginary and odd function of $f$ \\ an imaginary and even function of $t$ & an imaginary and even function of $f$ \\ a complex and even function of $t$ & a complex and even function of $f$ \\ a complex and odd function of $t$ & a complex and odd function of $f$ \end{tabular}

   Show that the Fourier transform of $g(t)$ may be expressed as
$$
G(f)=\int_{-\infty}^{\infty} g(t) \cos 2 \pi f t d t-j \int_{-\infty}^{\infty} g(t) \sin 2 \pi f t d t
$$

Hence, show that if $g(t)$ is an even function of $t$, then
$$
G(f)=2 \int_0^{\infty} g(n) \cos 2 \pi f t d t
$$
and if $g(t)$ is an odd function of $t$, then
$$
G(f)=-2 i \int_0^{\infty} g(t) \sin 2 \pi f t d t
$$

Hence, prove that:
\begin{tabular}{ll}
If $g(t)$ is: & Then $G(f)$ is: \\
a real and even function of $t$ & a real and even function of $f$ \\
a real and odd function of $t$ & an imaginary and odd function of $f$ \\
an imaginary and even function of $t$ & an imaginary and even function of $f$ \\
a complex and even function of $t$ & a complex and even function of $f$ \\
a complex and odd function of $t$ & a complex and odd function of $f$
\end{tabular}
Show more…
Modern digital and analog communication systems
Modern digital and analog communication systems
Ding, Zhi; Lathi,… 5th Edition
Chapter 3, Problem 4 ↓

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Step 1: Start with the definition of the Fourier transform of a function \( g(t) \): \[ G(f) = \int_{-\infty}^{\infty} g(t) e^{-j 2 \pi f t} dt \] where \( j \) is the imaginary unit.  Show more…

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Show that the Fourier transform of $g(t)$ may be expressed as $$ G(f)=\int_{-\infty}^{\infty} g(t) \cos 2 \pi f t d t-j \int_{-\infty}^{\infty} g(t) \sin 2 \pi f t d t $$ Hence, show that if $g(t)$ is an even function of $t$, then $$ G(f)=2 \int_0^{\infty} g(n) \cos 2 \pi f t d t $$ and if $g(t)$ is an odd function of $t$, then $$ G(f)=-2 i \int_0^{\infty} g(t) \sin 2 \pi f t d t $$ Hence, prove that: \begin{tabular}{ll} If $g(t)$ is: & Then $G(f)$ is: \\ a real and even function of $t$ & a real and even function of $f$ \\ a real and odd function of $t$ & an imaginary and odd function of $f$ \\ an imaginary and even function of $t$ & an imaginary and even function of $f$ \\ a complex and even function of $t$ & a complex and even function of $f$ \\ a complex and odd function of $t$ & a complex and odd function of $f$ \end{tabular}
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Key Concepts

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Fourier Transform
The Fourier transform is a mathematical operation that decomposes a time-domain signal into its constituent frequency components. This transform is defined by an integral that represents the signal as a combination of complex exponentials (or, equivalently, sine and cosine functions), which can be particularly useful for analyzing the spectral properties of the signal. It is a central tool in fields such as signal processing, physics, and engineering.
Even and Odd Functions
Even and odd functions have distinct symmetry properties that simplify integrals. An even function, satisfying f(t)=f(?t), has symmetric behavior about the vertical axis. In contrast, an odd function, satisfying f(t)=?f(?t), has antisymmetric behavior. These properties allow the integral expressions in the Fourier transform to be split and simplified, often reducing computational complexity by focusing on half of the domain.
Cosine and Sine Components
By expressing the complex exponential in the Fourier transform in terms of cosine and sine functions via Euler's formula, the transform can be separated into real and imaginary parts. The cosine term, being an even function, weighs the even component of the signal, while the sine term, being an odd function, weighs the odd component of the signal. This separation underpins the derivation of cosines and sines expressions in the Fourier transform when the input signal has specific parity.
Symmetry in the Frequency Domain
The symmetry properties of the time-domain function directly affect the symmetry properties of its Fourier transform in the frequency domain. When a function is even (or odd), its Fourier transform exhibits corresponding even (or odd) symmetry; additionally, the transform might be purely real or purely imaginary depending on the original function's characteristics. This relationship provides key insights into the spectral content and phase behavior of the signal.
Complex Fourier Transforms
In scenarios where the time-domain function is complex-valued, the Fourier transform also becomes complex and inherits specific symmetry properties based on the function's parity. For instance, if the complex function is even or odd, the corresponding transform will exhibit even or odd symmetry in the frequency domain. Understanding these properties is crucial for analyzing and interpreting signals that have both real and imaginary components.

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3.1-4 Show that the Fourier transform of g may be expressed as G(f) = ∫_{-∞}^{∞} g(t) cos 2πft dt − j ∫_{-∞}^{∞} g(t) sin 2πft dt Hence, show that if g(t) is an even function of t, then G(f) = 2 ∫_{0}^{∞} g(t) cos 2πft dt and if g(t) is an odd function of t, then G(f) = −2j ∫_{0}^{∞} g(t) sin 2πft dt Hence, prove that: If g(t) is: 1. a real and even function of t 2. a real and odd function of t 3. an imaginary and even function of t 4. a complex and even function of t 5. a complex and odd function of t

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