Question
Show that the function $f(x, y)=x y^{2}$ in Exercise $3,$ subject to $x+2 y=15,$ does not have an absolute minimum or maximum. (Hint: Solve the constraint for $x$ and substitute into $f . )$
Step 1
The constraint equation is $x+2y=15$. Solving for $x$ gives us $x=15-2y$. Show more…
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