Question
Show that the given equation is a solution of the given differential equation.$$y^{\prime \prime}+9 y=4 \cos x, \quad 2 y=\cos x$$
Step 1
The first derivative of $y$ with respect to $x$ is given by $y' = -\frac{1}{2}\sin x$. The second derivative of $y$ with respect to $x$ is given by $y'' = -\frac{1}{2}\cos x$. Show more…
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