00:04
So for this problem, we have the function given to us f of t.
00:23
F of t is equal to negative 16t squared plus the initial velocity times time, plus the position of the object, which is x -nat.
00:56
So the acceleration, the vertical motion, a -s -t, is given to us to be negative 30 -0.
01:06
2 feet per second.
01:27
So velocity is essentially the derivative i mean acceleration is essentially the derivative of the velocity.
01:38
So v prime of 2.
01:41
V prime of t is essentially acceleration.
01:46
So that is negative 32 feet per second squared.
01:56
So now we could integrate b prime of t.
02:04
We can integrate both sides.
02:12
So v of t velocity as a function of time is equal to the derivative is equal to the integral of negative 32 d t.
02:26
So what's the integral of this? that is easy negative 32 t plus a constant c sub 1...