Question
Show that the kinetic energy of a $1.0-\mathrm{kg}$ book tossed across the room at a speed of $3.0 \mathrm{~m} / \mathrm{s}$ is $4.5 \mathrm{~J} .$ (1 $\mathrm{J}$ is equivalent to $1 \mathrm{~kg}(\mathrm{~m} / \mathrm{s})^{2}$.)
Step 1
The kinetic energy of an object is given by the formula $KE = \frac{1}{2}mv^2$, where $m$ is the mass of the object and $v$ is its velocity. Show more…
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Show that the kinetic energy of a 1.0-kg book tossed across the room at a speed of 3.0 m/s is 4.5 J. (1 J is equivalent to 1 kg?m/s2.)
Kinetic energy $=\frac{1}{2}$ mass $\times$ speed $^{2} : \mathrm{KE}=\frac{1}{2} m v^{2}$ Show that the kinetic energy of a 1.0 -kg book tossed across the room at a speed of 3.0 $\mathrm{m} / \mathrm{s}$ is 4.5 $\mathrm{J} .$ ( 1 $\mathrm{J}$ is equivalent to 1 $\mathrm{kg} \cdot \mathrm{m} / \mathrm{s}^{2} . )$
write the formula of kinetic energy. find the kinetic energy of an object of mass 40 kg , object moves with velocity 900 m s-1.
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