Question
Show that the moment of inertia of a diatomic molecule is $\mu R_{e}^{2}$, where $\mu$ is the reduced mass, and $R_{\text {, }}$ is the equilibrium bond length.
Step 1
In a diatomic molecule, the axis of rotation is the bond connecting the two atoms. So, we can write the moment of inertia as: \[I = m_{1}r_{1}^{2} + m_{2}r_{2}^{2}\] Show more…
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Show that the moment of inertia of a diatomic molecule is $I=\mu r_{0}^{2},$ where $\mu$ is the reduced mass, and
A diatomic molecule consists of two atoms having masses $m_{1}$ and $m_{2}$ and separated by a distance $r .$ Show that the moment of inertia about an axis through the center of mass of the molecule is given by Equation $43.3, I=\mu r^{2} .$
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