00:03
In this example, we're going to look at the sum of three arbitrary vectors here, a, b, and c.
00:10
And we're going to show that if we rearrange the way we sum them, we will end up with the same vector sum regardless.
00:19
So for the vectors i've chosen, i have a, which has components 5 and 5 through the x and y respectively.
00:27
Vector b has an x component 0, y component of 3, and vector c has an x component of minus 3, and y component of zero.
00:36
So i've drawn those here just to illustrate what they look like.
00:40
So now to sum these all together for the first sum here, we're just going to do what we always do, which is some all of the individual components in order to get the components of d.
00:55
So to get d sub x, we're just going to sum all the x components of each of our individual vectors.
01:03
So to do this, we'll want a sub x plus b sub x plus c sub x.
01:10
Which is going to be 5 plus 0 minus 3.
01:17
So d sub x should be 2.
01:23
Now if we do the same thing for d sub y, we'll know that d sub y is the sum of a sub y plus b sub y plus c sub y, which is just going to be 5 plus 3 plus 0, which is 8.
01:44
Okay.
01:47
So effectively we've now calculated d since we have the components.
01:51
So this vector is fully specified...