Question
Show that the points $\mathbf{R}(-4,4), \mathbf{S}(-2,-4)$, and $\mathbf{T}(6,-2)$ are the vertices of an isosceles triangle.
Step 1
The distance formula is given by: \[ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} \] Substituting the coordinates of \(\mathbf{R}\) and \(\mathbf{S}\): \[ d_{RS} = \sqrt{((-2) - (-4))^2 + ((-4) - 4)^2} = \sqrt{(2)^2 + (-8)^2} = \sqrt{4 + 64} = \sqrt{68} = Show more…
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