Question
Show that the radius of gyration of a thin rod of length $l$ about an axis through its centre and perpendicular to the rod is $\frac{i}{2 \sqrt{3}}$.An equilateral triangle $A B C$ is made of three identical thin rods each of length 1 . Find the radius of gyration of the triangle about an axis through A, perpendicular to the plane of $\mathrm{ABC}$.
Step 1
Step 1: The moment of inertia, $I$, of a thin rod of length $l$ about an axis through its centre and perpendicular to the rod is given by the formula $I = \frac{1}{12}ml^2$, where $m$ is the mass of the rod. Show more…
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Show that the radius of gyration of a thin rod of length $l$ about an axis through its centre and perpendicular to the rod is $\frac{i}{2 \sqrt{3}}$. An equilateral triangle $A B C$ is made of three identical thin rods each of length 1 . Find the radius of gyration of the triangle about an axis through A, perpendicular to the plane of $\mathrm{ABC}$.
Integration applications 2
Test exercise
The radius of gyration of an uniform rod of length l about an axis passing through one of its ends and perpendicular to its length is (a) $\frac{1}{\sqrt{2}}$ (b) $\frac{l}{3}$ (c) $\frac{1}{\sqrt{3}}$ (d) $\frac{1}{2}$
The radius of gyration of a uniform rod of length $L$ about an axis passing through its centre of mass and perpendicular to its length is (a) $L / \sqrt{12}$ (b) $t^{2} / 12$ (c) $L / \sqrt{3}$ (d) $L \underline{1} \sqrt{2}$
Rotational Motion
Round 1
Transcript
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