Question
Show that the rotation matrices$$d_{m^{\prime} m}^j(\theta)=\left\langle j m^{\prime}\left|e^{-i \theta J_2}\right| j m\right\rangle$$for $j=\frac{1}{2}$ and $j=1$ are$$j=\frac{1}{2}\left\{\begin{array}{l}d_{++}=d_{--}=\cos \frac{1}{2} \theta \\d_{-+}=-d_{+-}=\sin \frac{1}{2} \theta\end{array}\right.$$where \pm denote $m= \pm \frac{1}{2}$, respectively, and$$j=1\left\{\begin{array}{l}d_{01}=-d_{10}=-d_{0-1}=d_{-10}=\sqrt{\frac{1}{2}} \sin \theta \\d_{11}=d_{-1-1}=\frac{1}{2}(1+\cos \theta) \\d_{-11}=d_{1-1}=\frac{1}{2}(1-\cos \theta) \\d_{00}=\cos \theta .\end{array}\right.$$
Step 1
The indices \( m \) and \( m' \) range over \(-j, -j+1, \ldots, j\), and \( \theta \) is the rotation angle about the y-axis. Show more…
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