Question

Show that the solid angle subtended by a sphere of radius $r$ at a distance $R$ from its centre is $4 \pi r^2 / R^2$. Hence, by reasoning directly from the geometry, show that for a spherical body at the centre of a spherical cavity, the proportion of the radiation emitted from the cavity wall that hits the sphere is $r^2 / R^2$, if the emission is isotropic. Derive the same result using the shape factor reciprocity relation.

   Show that the solid angle subtended by a sphere of radius $r$ at a distance $R$ from its centre is $4 \pi r^2 / R^2$. Hence, by reasoning directly from the geometry, show that for a spherical body at the centre of a spherical cavity, the proportion of the radiation emitted from the cavity wall that hits the sphere is $r^2 / R^2$, if the emission is isotropic. Derive the same result using the shape factor reciprocity relation.
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Thermodynamics: A complete undergraduate course
Thermodynamics: A complete undergraduate course
Andrew M. Steane 1st Edition
Chapter 20, Problem 4 ↓

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Step 1

The solid angle is defined as the ratio of the surface area of a portion of a sphere to the square of its radius. The surface area of a portion of a sphere is given by $4 \pi r^2$, and the square of the radius is $r^2$.  Show more…

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Show that the solid angle subtended by a sphere of radius $r$ at a distance $R$ from its centre is $4 \pi r^2 / R^2$. Hence, by reasoning directly from the geometry, show that for a spherical body at the centre of a spherical cavity, the proportion of the radiation emitted from the cavity wall that hits the sphere is $r^2 / R^2$, if the emission is isotropic. Derive the same result using the shape factor reciprocity relation.
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