Show that the solution of the initial value problem y^'=x+y, y(x0)=y0 is y=-1-x+(1+x0+y0) e^x-

Name: Problem 25, Chapter 9: Thomas Calculus
Uploaded: 2020-02-22T03:16:50-08:00
Duration: 1 min 52 s
Channel: Clarissa Noh
Description: Show that the solution of the initial value problem y^'=x+y, y(x0)=y0 is y=-1-x+(1+x0+y0) e^x-x0.

Question

Show that the solution of the initial value problem y^'=x+y,   y(x0)=y0 is y=-1-x+(1+x0+y0) e^x-

Clarissa Noh · Accepted Answer

step 1 It&#x27;s Clarissa would numerate here. So we have to differentiate the function with respect to X. S

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