00:01
Hi there, so for this problem, we need to show that the variation of atmospheric pressure and an altitude is given by the following expression, p -0, which is the atmospheric pressure, this times the exponential of minus alpha times y, where alpha is defined as the density times the acceleration due to gravity, and this divided by the atmospheric pressure.
00:31
So, to solve this problem, to show this expression, we know that the incremental version of the pressure minus the atmospheric pressure, which is the density times acceleration due to gravity, times the height, we can put the differential of this as just minus the density, the acceleration due to gravity, and this is the differential of the height.
00:58
We assume that the density of air is proportional to the pressure, or we can say that the pressure divided by the density is equal to the atmospheric pressure divided by the initial density.
01:12
So combining these two equations, we have the following.
01:15
Then we will have that the differential in the pressure can be written as minus the pressure times the density, the initial density, divided by the atmospheric pressure, these times acceleration due to gravity, and this.
01:28
This times the differential in the altitude.
01:32
Now we separate the variables from here.
01:35
So we can have that the differential in pressure, divided by the pressure, is equal to minus the acceleration due to gravity.
01:47
The initial density, this divided by the atmospheric pressure, and this times the differential in the height.
01:54
Now we integrate both sides of this expression.
01:56
So for the left side, we have have the integral from the atmospheric pressure to the pressure p of the differential in pressure divided by the pressure.
02:08
And then this is equal to minus the acceleration due to gravity.
02:12
The density, row sub zero.
02:15
This divided by the pressure p sub zero, and the integral from zero to y of the differential in y...