Question
Show that the vectors are orthogonal with respect to the standard inner product on $P_{2}$.$$\mathbf{p}=2-3 x+x^{2}, \mathbf{q}=4+2 x-2 x^{2}$$
Step 1
The inner product in the space of polynomials of degree two is defined as the integral from -1 to 1 of the product of the two polynomials. So, we have: \[\langle p, q\rangle = \int_{-1}^{1} (2-3x+x^{2})(4+2x-2x^{2}) dx\] Show more…
Show all steps
Your feedback will help us improve your experience
Anthony Ramos and 67 other Calculus 3 educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
Show that the vectors are orthogonal with respect to the standard inner product on $P_{2}$. $$\mathbf{p}=-1-x+2 x^{2}, \mathbf{q}=2 x+x^{2}$$
Inner Product Spaces
Angle and Orthogonality in Inner Product Spaces
Let $P_{2}$ have the cvaluation inner product at the points $$ x_{0}=-2, \quad x_{1}=0, \quad x_{2}=2 $$ Show that the vectors $\mathbf{p}=x$ and $\mathbf{q}=x^{2}$ are orthogonal with respect to this inner product.
Show that the vectors are not orthogonal with respect to the Euclidean inner product on $R^{2}$, and then find a value of $k$ for which the vectors are orthogonal with respect to the weighted Euclidean inner product $(\mathbf{u}, \mathbf{v})=2 u_{1} v_{1}+k u_{2} v_{2}$. $$\mathbf{u}=(2,-4), \mathbf{v}=(0,3)$$
Transcript
18,000,000+
Students on Numerade
Trusted by students at 8,000+ universities
Watch the video solution with this free unlock.
EMAIL
PASSWORD