00:01
Brass to show that solon's algorithm requires at most log -in iterations to produce a minimum spanning tree from a connected, undirected, weighted graph with n vertices.
00:18
So, first of all, let g be a connected, weighted, undirected graph with n vertices.
00:47
Now, recall from a previous exercise that solon's algorithm has, has no more than the floor of n over 2 to the k trees remaining after the first step and the next k minus 1 steps of the algorithm have been carried out.
02:01
Now let's assume that n is a power of 2.
02:16
So we'll want to find an integer m such that n is equal to 2 to the m.
02:33
You know the maximum number of iterations possible then occurs when the floor of n over 2 the k is equal 1.
03:12
So essentially we have the n over 2 to the k.
03:16
Well this is the same as the floor of n over, or instead of n we have 2 to the m over 2 to the k...