11) to get the processes for $\ln g$ and $\ln h$.
According to equation (14A.11), we have:
$$
d\ln g = \frac{1}{g}dg - \frac{1}{2} \left(\frac{1}{g}\right)^2 dg = \frac{1}{g}dg - \frac{1}{2g^2}dg = \frac{1}{g}\left(1 - \frac{1}{2g}\right)dg
$$
Similarly, we
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