00:01
So typically when we have one like this, we can just kind of use a special situation like the similar squares or this difference of squares or something like that the difference of tubes some of tubes but for this one let's just say we try to factor the normal way.
00:15
Okay, so let's just say we have x squared technically we have a zero x term here then we have plus four so when we do a times c we have one times four which gives this four we need to find the factored pairs that ends up with four.
00:33
So we have one and four and two and two.
00:36
We need to find a way to combine these two terms, one of the factor pairs, to get zero there.
00:42
So one and four, we can't add or subtract them to get zero.
00:45
We can do two and two.
00:47
So we're going to use two and two.
00:50
So here we have x and two.
00:55
But wait a minute.
00:56
So when we do this, though, the only way that we can have two and two is if, one is positive and one is negative because it has to equal zero...