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Showing the details, find, graph, and discuss the solution.$$\begin{aligned}&y^{\prime \prime}-y=108\left(t-\frac{1}{2}\right)-1008(t-1)\\&y(0)=10, \quad y^{\prime}(0)=1\end{aligned}$$
Step 1
The homogeneous equation is given by: $$y'' - y = 0$$ The characteristic equation of this homogeneous equation is: $$r^2 - 1 = 0$$ Solving this equation gives us the roots r = 1 and r = -1. Therefore, the homogeneous solution is given by: $$y_h(t) = c_1 e^{t} + Show more…
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