For sides \( AB \) and \( CD \) (thickness = 1 mm):
\[
q_{AB} = \tau \cdot t_{AB} = (5.5 \times 10^7 \, \text{Pa}) \cdot (1 \times 10^{-3} \, \text{m}) = 5.5 \times 10^4 \, \text{N/m}
\]
For sides \( AC \) and \( BD \) (thickness = 2 mm):
\[
q_{AC} =
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