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Shown is the graph of traffic on an Internet service provider's T1 data line from midnight to 8:00 AM. $ D $ is the data throughput, measured in megabits per second. Use the Midpoint Rule to estimate the total amount of data transmitted during that time period.

$\approx 15696$ Mbits $\quad$ (answer may vary depending on your estimates)

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okay. We know the central from zero to a of D of t did Cheap is gonna be 1/3 time's d of T zero plus four times D of t one plus two times D of T, too. It was four times D v D three plus two terms D of de Flore plus four times D of G five plus two times DVD six plus four times D of G seven close five times Sorry, plus one times d of t eight. Using a calculator for this you end up with 4.36 however, are not done. We have to multiply this by 3600 seconds because that's the number of seconds in an hour, seconds and seconds. Cancel. This is dimensional analysis and we end up with 15 696 mega bits.