💬 👋 We’re always here. Join our Discord to connect with other students 24/7, any time, night or day.Join Here!

# Shown is the power consumption in the province of Ontario, Canada, for December 9, 2004 ($P$ is measured in megawatts; $t$ is measured in hours starting at midnight). Using the fact that power is the rate of change of energy, estimate the energy used on that day.

## $$475,200$$

Integrals

Integration

### Discussion

You must be signed in to discuss.
##### Catherine R.

Missouri State University

##### Heather Z.

Oregon State University

##### Kristen K.

University of Michigan - Ann Arbor

##### Michael J.

Idaho State University

Lectures

Join Bootcamp

### Video Transcript

you were trying to estimate the energy used on that day. We have the integral 0 to 24 p v T. D. T. Now using the midpoint roll with 12 sub intervals and delta T and other words changing tease, too. This is equivalent to pee of one p of three was p of five. So we're just continuing onwards with the intervals and then this only two multiplied by two to get 475400 megawatt hours.

#### Topics

Integrals

Integration

##### Catherine R.

Missouri State University

##### Heather Z.

Oregon State University

##### Kristen K.

University of Michigan - Ann Arbor

##### Michael J.

Idaho State University

Lectures

Join Bootcamp