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Shown is the power consumption in the province of Ontario, Canada, for December 9, 2004 ($P$ is measured in megawatts; $t$ is measured in hours starting at midnight). Using the fact that power is the rate of change of energy, estimate the energy used on that day.

$$475,200$$

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Catherine R.

Missouri State University

Heather Z.

Oregon State University

Kristen K.

University of Michigan - Ann Arbor

Michael J.

Idaho State University

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Video Transcript

you were trying to estimate the energy used on that day. We have the integral 0 to 24 p v T. D. T. Now using the midpoint roll with 12 sub intervals and delta T and other words changing tease, too. This is equivalent to pee of one p of three was p of five. So we're just continuing onwards with the intervals and then this only two multiplied by two to get 475400 megawatt hours.

Topics

Integrals

Integration

Catherine R.

Missouri State University

Heather Z.

Oregon State University

Kristen K.

University of Michigan - Ann Arbor

Michael J.

Idaho State University

Lectures

Join Bootcamp