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Shown is the power consumption in the province of Ontario, Canada, for December 9, 2004 ($ P $ is measured in megawatts; $ t $ is measured in hours starting at midnight). Using the fact that power is the rate of change of energy, estimate the energy used on that day.

$$475,200$$

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you were trying to estimate the energy used on that day. We have the integral 0 to 24 p v T. D. T. Now using the midpoint roll with 12 sub intervals and delta T and other words changing tease, too. This is equivalent to pee of one p of three was p of five. So we're just continuing onwards with the intervals and then this only two multiplied by two to get 475400 megawatt hours.