00:01
Okay, welcome.
00:02
So for this problem, we're given the following graph of angle versus time, and the first thing we're asked to do is to describe its position.
00:09
So it starts at theta equal 4 pi, which basically means it's gone around a circle twice, and moves backward a total of six pi radians in one second.
00:39
So we can see that because it goes from four pi to two pi to zero to negative two pi.
00:44
So that's moving backwards and that happens all in one second.
00:48
And then it remains stationary for one second.
01:01
That's that's not changing its angle.
01:04
And then it moves forward 2 pi radians in the next 2 seconds.
01:21
So it goes from negative 2 pi all the way back to 0.
01:24
So that's what this thing does.
01:26
Now if we want a we were also asked for part b to draw an omega in radians per second versus time in seconds diagram.
01:37
Now we'll want to have the same time intervals.
01:40
Two, three, four.
01:43
Now for omega, we're going to have, so we're really only going to have three relevant speeds.
01:51
One is going to be negative six pi radiance per second.
01:56
So it'll be negative...