00:01
So we are given a graph of the wave function that looks something like this.
00:07
First, minus c over 2 from minus 2 to minus 1, in the middle from minus 1 to 1c, and then again, from 1 to 2 is minus c over 2.
00:19
To know this c, we need to take into account the normalization of the wave function, this condition, is 1.
00:31
So we get that the absolute value of c over 2 squared from minus 2 to minus 1 integrated plus the integral from minus 1 to 1 of the integral of c squared plus finally from 1 to 2 the absolute value of c over 2 square is 3 integral summed into equal to 1 and this 3 integral summed into equal to 1.
01:19
And this is equivalent to having, so taking the constant out, and having, so it's, you can just do the integral from 0 to 1 of 1.
01:46
So, dx, oh, i'm missing the x here.
02:01
Okay, so the x plus this should be two times, and then two times from one to two, and this this is 1 .5 squared.
02:25
This gives, so the first one is 1, the first integral, and the second one is 1 fourth integrated gives x over 4 between 1 and 2 is 1 1 1 .5 minus 1 4, which is 1 4.
03:05
This is 1.
03:06
So this whole thing is 2 times 5 fourths.
03:21
So we have that c is plus or minus.
03:28
And we'll take the, we can take the positive value.
03:33
So the plus it's okay...