Question
Shrinking cube The volume of a cube decreases at a rate of $0.5 \mathrm{ft}^{3} / \mathrm{min} .$ What is the rate of change of the side length when the side lengths are $12 \mathrm{ft} ?$
Step 1
We have a cube that is shrinking at a rate of $0.5 \mathrm{ft}^{3} / \mathrm{min}$. This means that the volume of the cube is decreasing at this rate. We denote this as $\frac{dV}{dt} = -0.5 \mathrm{ft}^{3} / \mathrm{min}$. Show more…
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The volume of a cube decreases at a rate of $0.5 \mathrm{ft}^{3} / \mathrm{min} .$ What is the rate of change of the side length when the side lengths are $12 \mathrm{ft} ?$
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The volume of a cube decreases at a rate of 0.4 ft^3 /min. What is the rate of change of the side length when the side lengths are 12ft? A. Write an equation relating the volume of a cube, V, and an edge of the cube, s? B. Differentiate both sides of the equation with respect to t dV/dt = ____ ds/dt C. The rate of change of the side length when the side lengths are 12 ft is?
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