00:01
So we know that the probability that a trait is passed on by a parent that has it is 50%.
00:07
So what's the probability that two parents pass on and have a child that has sickle cell? so the probability that two parents pass on and you have a child who has the sickle cell.
00:22
And in order for that to happen, the child has to have both genes, has to have two sickle cell genes.
00:28
So that would be 0 .5 times 0 .5.
00:32
So the probability is 0 .25 that the parents will have a child that has sickle cell.
00:42
Now, part b asks if they have five children, and we know that the probability that they have a child with sickle cell is 0 .25.
00:52
And let's say x is the number of children that have sickle cell of those 5.
01:00
We want to know on this one, what's the probability that at least one of them has sickle cell.
01:07
And we know that that is complementary to none of the children having sickle cell.
01:13
And so that means this is a binomial setting, and we always have that combination and a vibe choose, and we don't want any of them to have sickle cell.
01:21
Well, sickle cell is 0 .25, and we don't want any of those.
01:25
That's a 0 .75.
01:26
And we have 0 .75, and these would be children that wouldn't have.
01:30
The trait and that would be to the fifth power and when we do that calculation we end up getting 0 .76 to 7 so i have about a 76 % chance of having at least one child having sickle cell.
01:45
Part c we want to get the probability distribution for this setting and so we know that this is going to be that combination of 5 choose i times 0 .25 to the i and 0 .75 to the 5 to the 5 .5 minus i.
02:04
And we can use our binomial pdf for this.
02:08
And let's quick just set up the table.
02:11
And we know that they could have none, one, two, three, four, and sadly, all five could have a single cell...