Question
Silver metal reacts with chlorine $\left(\mathrm{Cl}_{2}\right)$ to yield silver chloride. If 2.00 $\mathrm{g}$ of Ag reacts with 0.657 $\mathrm{g}$ of $\mathrm{Cl}_{2},$ what is the empirical formula of silver chloride?
Step 1
The molar mass of silver is 107.87 g/mol and that of chlorine is 70.90 g/mol. For silver, we have: \[ \frac{2.00 \, \text{g}}{107.87 \, \text{g/mol}} = 0.0185 \, \text{mol} \] Show more…
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