Simple Harmonic Oscillator. Suppose that a particle of mass $m$ is trapped not in a square well, but in one whose potential energy is that of a simple harmonic oscillator:
$U(x)=\frac{1}{2} C x^{2} .$ That is, if the particle is displaced from $x=0$ a restoring force $F=-C x$ acts on it, where $C$ is constant.
(a) Sketch this potential energy.
(b) Show that $\psi=A e^{-B x^{2}}$ is a solution to the Schrödinger equation and that the energy of this state is $E=\frac{1}{2} \hbar \omega,$ where $\omega=\sqrt{C / m}$ (as classically, Eq. $14-5$ ) and $B=m \omega / 2 \hbar$. [Note: This is the ground state, and this energy $\frac{1}{2} \hbar \omega$ is the zero-point energy for a harmonic oscillator. The energies of higher states are $E_{n}=\left(n+\frac{1}{2}\right) \hbar \omega,$ where $n$ is an integer.